x^2-2x+40=5

Solution for x^2-2x+40=5 equation:

Simplifying
x2 + -2x + 40 = 5

Reorder the terms:
40 + -2x + x2 = 5

Solving
40 + -2x + x2 = 5

Solving for variable 'x'.

Reorder the terms:
40 + -5 + -2x + x2 = 5 + -5

Combine like terms: 40 + -5 = 35
35 + -2x + x2 = 5 + -5

Combine like terms: 5 + -5 = 0
35 + -2x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-35' to each side of the equation.
35 + -2x + -35 + x2 = 0 + -35

Reorder the terms:
35 + -35 + -2x + x2 = 0 + -35

Combine like terms: 35 + -35 = 0
0 + -2x + x2 = 0 + -35
-2x + x2 = 0 + -35

Combine like terms: 0 + -35 = -35
-2x + x2 = -35

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -35 + 1

Reorder the terms:
1 + -2x + x2 = -35 + 1

Combine like terms: -35 + 1 = -34
1 + -2x + x2 = -34

Factor a perfect square on the left side:
(x + -1)(x + -1) = -34

Can't calculate square root of the right side.

The solution to this equation could not be determined.